首页 > ✿ ACE > ♦ Ace SCS CB EB 紧急安全用 工業油壓吸震器 > ★ 天车 港口升降起重机&紧急设计运用设计运用范例之计算公式
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天车 港口升降起重机&紧急设计运用设计运用范例之计算公式
14. 1台移动车 2支吸震器对撞
公式
W1 = 0.25 x m x V²
W2 = F x s
W3 = W1 + W2
W4 = W3 x C
VD = V ÷ 2
Me = 2 x W3 ÷ VD²
已知參數
m =5,000 Kg
V =2 m/s
F =3,500 N
C =10 /hr
S =0.15 m
計算
W1 = 0.25 x 5,000 x 2² =5000 Nm
W2 = 3,500 x 0.15 =525 Nm
W3 = 5,000 + 525 =5,525 Nm/C
W4 = 5,525 x 10 =55,250 Nm/hr
Me = 2 x 5,525 ÷ 1² =11,050 Kg
建议选用:自力补偿式: CA 2x6-2
15. 2台移动车 1支吸震器对撞
公式
W1 =
W2 = F x s
W3 = W1 + W2
W4 = W3 x C
VD = v1 + v2
Me = 2 x W3 ÷ VD²
已知參數
m1 =7,000 Kg
F =5,000 N
V1 =1.2 m/s
C =20 /hr
m2 =1,000 Kg
V2 =0.5 m/s
S =0.127 m
計算
W1 = =5,950 Nm
W2 = 5,000 x 0.127 =635 Nm
W3 = 5,950 + 635 =6,585 Nm/C
W4 = 6,585 x 20 =131,700 Nm/hr
VD = 1.2 + 0.5 =1.7 m/s
Me = 2 x 6,585 ÷ 1.7² =4,557 Kg
建议选用:自力补偿式: CA 3x5-1
16. 2台移动车 2支吸震器对撞
公式
W1 =
W2 = F x s
W3 = W1 + W2
W4 = W3 x C
VD =(v1 + v2) ÷ 2
Me = 2 x W3 ÷ VD²
已知參數
m1 =7,000 Kg
F =5,000 N
V1 =1.2 m/s
C =20 /hr
m2 =1,000 Kg
V2 =0.5 m/s
S =0.1 m
計算
W1 = =5,950 Nm
W2 = 5,000 x0.1 =500 Nm
W3 =(5,950÷2) + 500 =3,475 Nm/C
W4 = 3,475 x 20 =69,500 Nm/hr
VD =(1.2 + 0.5)÷2 =0.85 m/s
Me = 2 x 3,475 ÷ 0.85² =358.9 Kg
建议选用:自力补偿式: CA 2x4-2
有效重量值 (Me) 计算说明
A. 没有附加推进力
Me = m
参数说明
m =100 Kg
VD =v= 2 m/s
W1 =W3 = 200 Nm
Me =2x200÷2²=100Kg
Me = m
B. 有附加推进力
Me = 2 x W3 ÷ VD²
参数说明
m =100 Kg
F =2,000 N
VD =v= 2 m/s
s =0.1 m
W1 = 200 Nm
W2 = 200 Nm
W3 = 400 Nm
Me =2x400÷2²=200Kg
C. 没有附加推进力
Me = m
参数说明
m =20 Kg
VD =v = 2 m/s
W1 =W3 = 40 Nm
Me =2x200÷2²=20Kg
Me = m
D. 有附加推进力
Me = 2 x W3 ÷ VD²
参数说明
m =100 Kg
v =2 m/s
VD =0.5 m/s
W1 = W3 = 40 Nm
Me =2x40÷0.5²=320Kg
反作用力 Q(N)
Q = ( 1.5 x W3 ) ÷ S
停止时间 t(s)
t = ( 2.6 x S ) ÷ VD²
a减速率 a (m/s)
a = ( 0.75 x VD² ) ÷ S
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